3sin^2x+5cosx-1=10

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Solution for 3sin^2x+5cosx-1=10 equation: 


Simplifying
3sin2x + 5cosx + -1 = 10

Reorder the terms:
-1 + 5cosx + 3in2sx = 10

Solving
-1 + 5cosx + 3in2sx = 10

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 5cosx + 1 + 3in2sx = 10 + 1

Reorder the terms:
-1 + 1 + 5cosx + 3in2sx = 10 + 1

Combine like terms: -1 + 1 = 0
0 + 5cosx + 3in2sx = 10 + 1
5cosx + 3in2sx = 10 + 1

Combine like terms: 10 + 1 = 11
5cosx + 3in2sx = 11

Add '-3in2sx' to each side of the equation.
5cosx + 3in2sx + -3in2sx = 11 + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
5cosx + 0 = 11 + -3in2sx
5cosx = 11 + -3in2sx

Divide each side by '5osx'.
c = 2.2o-1s-1x-1 + -0.6in2o-1

Simplifying
c = 2.2o-1s-1x-1 + -0.6in2o-1

Reorder the terms:
c = -0.6in2o-1 + 2.2o-1s-1x-1

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